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10/29/2004 02:11:59 AM · #101 |
How much would a decent telescope cost for this?
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10/29/2004 07:05:05 AM · #102 |
Originally posted by kidchico:
How much would a decent telescope cost for this? |
$125 dollar will get you a good shot of the moon.
My shots though...with a 200mm (lol!)
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10/29/2004 09:46:12 AM · #103 |
Still bummed that I was clouded out here in Wisconsin, but I've enjoyed seeing everybody's shots, thanks for posting them. Take a look at today's Astronomy Pic of the Day here, taken by NASA scientist and eclipse guru Fred Espenak. Nice artistic shot by a scientist!
BTW, if you look after Friday is over, you'll get Saturday's pic. Use the archives to go back to October 29. While you're at it, take a look at this amazing shot from their archives (warning: shameless self promotion).
Message edited by author 2004-10-29 09:48:26. |
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10/29/2004 09:49:05 AM · #104 |
Originally posted by strangeghost:
Still bummed that I was clouded out here in Wisconsin, but I've enjoyed seeing everybody's shots, thanks for posting them. Take a look at today's Astronomy Pic of the Day here, taken by NASA scientist and eclipse guru Fred Espenak. Nice artistic shot by a scientist!
BTW, if you look after Friday is over, you'll get Saturday's pic. Use the archives to go back to October 29. While you're at it, take a look at this amazing shot from their archives (warning: shameless self promotion). |
Great moon shot. ... this eclipse is perhaps remarkable for being the first total lunar eclipse to occur during a World Series baseball game.
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10/29/2004 09:56:02 AM · #105 |
Originally posted by Gordon:
Great moon shot. ... this eclipse is perhaps remarkable for being the first total lunar eclipse to occur during a World Series baseball game. |
If that's what it takes for the Red Sox to win I'm afraid Boston is facing another long drought.
Great pics people -- I really like the collages. I just got a couple of not-too-good shots (mostly I under-exposed them). |
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10/29/2004 10:17:33 AM · #106 |
Originally posted by kidchico:
How much would a decent telescope cost for this? |
Depends on what you mean by decent.
For getting started, your naked eye and a good pair of binoculars is the best way to learn your way around the night sky. Get a nice pair 10x50 binos and you're on your way....
As for telescopes:
You can get a department store special for ~$70.
You can get something like a 14" Schmidt-Cassegrain and spend several thousand dollars.
You can spend anywhere in between. |
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10/29/2004 11:07:59 AM · #107 |
Originally posted by strangeghost:
Still bummed that I was clouded out here in Wisconsin, but I've enjoyed seeing everybody's shots, thanks for posting them. Take a look at today's Astronomy Pic of the Day here, taken by NASA scientist and eclipse guru Fred Espenak. Nice artistic shot by a scientist! |
Took more thinking that it should, but realised that Espenak's pictures are re-orientated so that the north axis of the moon is 'up'
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10/29/2004 01:06:10 PM · #108 |
Originally posted by Gordon:
Originally posted by strangeghost:
Still bummed that I was clouded out here in Wisconsin, but I've enjoyed seeing everybody's shots, thanks for posting them. Take a look at today's Astronomy Pic of the Day here, taken by NASA scientist and eclipse guru Fred Espenak. Nice artistic shot by a scientist! |
Took more thinking that it should, but realised that Espenak's pictures are re-orientated so that the north axis of the moon is 'up' |
How do you figure? It looks like mine does. And I didn't re-orient anything.
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10/29/2004 03:11:22 PM · #109 |
Originally posted by atsxus:
How do you figure? It looks like mine does. And I didn't re-orient anything. |
If the camera is mounted on an equatorial mount (like piggyback on an eq. telescope), the image will automatically be de-rotated (north will be up). If it's mounted alt/az, (like on a tripod) the image will be rotated unless the moon was shot exactly on the meridian (due south for N. hemisphere observers). Espenak's stuff would almost certainly be eq. mounted since he's probably shooting through a good astronomical scope. |
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10/29/2004 03:21:20 PM · #110 |
Originally posted by atsxus:
Originally posted by Gordon:
Originally posted by strangeghost:
Still bummed that I was clouded out here in Wisconsin, but I've enjoyed seeing everybody's shots, thanks for posting them. Take a look at today's Astronomy Pic of the Day here, taken by NASA scientist and eclipse guru Fred Espenak. Nice artistic shot by a scientist! |
Took more thinking that it should, but realised that Espenak's pictures are re-orientated so that the north axis of the moon is 'up' |
How do you figure? It looks like mine does. And I didn't re-orient anything. |
Yours is actually rotated by about 20-30 degrees from North. In particular look at the location of the Mare Crisium (the dark spot on the top right). In your shot it is at about 1pm. If you look at Espenak's shot, it is at about 3pm. I assume you took your shot somewhere in the north of the US.
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10/29/2004 03:22:27 PM · #111 |
Originally posted by strangeghost:
Originally posted by atsxus:
How do you figure? It looks like mine does. And I didn't re-orient anything. |
If the camera is mounted on an equatorial mount (like piggyback on an eq. telescope), the image will automatically be de-rotated (north will be up). If it's mounted alt/az, (like on a tripod) the image will be rotated unless the moon was shot exactly on the meridian (due south for N. hemisphere observers). Espenak's stuff would almost certainly be eq. mounted since he's probably shooting through a good astronomical scope. |
That's cool. Hadn't heard about an equatorial mount before. Thanks for the info! Now that's what I call a tripod head
Message edited by author 2004-10-29 15:23:53.
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