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07/25/2010 07:10:03 PM · #26 |
Originally posted by zxaar:
Originally posted by NiallOTuama:
Originally posted by zxaar:
you are math-brain like me, you will like this one:
if you have 23 friends then the probability that two of them share same birthday is 50%.
Here is a interesting read about it.
//en.wikipedia.org/wiki/Birthday_problem |
That has won me a drink or two in my past. |
really.
I really did not know it for long time and i used to think i was good at maths. |
Yeah. It works best at large gatherings of people. I haven't done it with fewer than 25 people, and it has worked on two occasions.
Me: "Do you think two people here have the same birthday?"
Them: "No. Not a chance!"
Me: "I don't know."
Them: "Wanna bet?"
Me: "A drink!"
Them: "Deal."
You should read freakonomics.
Message edited by author 2010-07-25 19:10:44.
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07/25/2010 07:21:02 PM · #27 |
Originally posted by zxaar:
Originally posted by vawendy:
Originally posted by GeneralE:
There have been several ties for ribbons. Depending on the underlying math, we may end up with two second-places and no third, but it will take personal intervention by Langdon if that's to happen. |
I was curious and went and did the math, because I figured she must have just beaten me by a tiny amount.
It's actually an exact tie -- 1427 points divided by 206 in both cases. That's so bizarre! |
you are math-brain like me, you will like this one:
if you have 23 friends then the probability that two of them share same birthday is 50%.
Here is a interesting read about it.
//en.wikipedia.org/wiki/Birthday_problem |
We actually did that in my statistics class in 11th grade. It worked! It still boggles my mind, even if I understand the math.
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07/25/2010 07:36:53 PM · #28 |
I like the way SC and Langdon have dealt with this tie of 2nd and 3rd place, actually.
Why should I move up a place (from 36th to 35th) just because two people far above me had the same score?
Well done.
Message edited by author 2010-07-25 19:38:45. |
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07/25/2010 07:38:16 PM · #29 |
| The thing with the "birthday problem" is that most people don't think of it as "any two people" sharing some birthday -- we are more mentally conditioned to think of it in terms of "what are the odds that "those two people'" share the birthday. |
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