| Author | Thread |
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01/04/2014 05:07:04 PM · #23451 |
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01/04/2014 05:07:54 PM · #23452 |
| Spork rhymes with Dork and All rhymes with Fall and that's what you just did. I win again. |
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01/04/2014 05:10:38 PM · #23453 |
| your bucket's got a hole innit. |
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01/04/2014 05:11:39 PM · #23454 |
*kick!*
...no more bucket. |
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01/04/2014 10:38:30 PM · #23455 |
art finally kicked the bucket - i win.
say it ain't so and i'll kick yer can. |
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01/05/2014 12:30:38 AM · #23456 |
| It ain't so, but I just purchased a farm - is that close enough? |
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01/07/2014 03:51:20 AM · #23457 |
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01/07/2014 03:51:39 AM · #23458 |
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01/07/2014 03:51:57 AM · #23459 |
Originally posted by Art Roflmao:
Hello |
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01/07/2014 03:54:07 AM · #23460 |
By the way, as funny as it may sound, I just now realized I was the first player of this game... Hmmph. I guess that means I'm actually the biggest loser (in so many ways) doesn't it? ;)
ETA: And it looks like I've lost a few more than 23,000 times now in fact.
Message edited by author 2014-01-07 03:55:09. |
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01/07/2014 03:54:40 AM · #23461 |
Don't think that interrupting my two day streak went unnoticed, Cory. I'm plotting revenge as we speak.
...well not really, I'm eating a salad, but I WILL plot later. Count on it. |
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01/07/2014 03:56:02 AM · #23462 |
Originally posted by Art Roflmao:
Don't think that interrupting my two day streak went unnoticed, Cory. I'm plotting revenge as we speak.
...well not really, I'm eating a salad, but I WILL plot later. Count on it. |
plot it on the sides of yer toilet.
Salad Shooter! |
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01/07/2014 03:58:09 AM · #23463 |
| I was first, and I will be last... No other can reign over this domain. |
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01/07/2014 04:10:31 AM · #23464 |
Young Josh has a lot to answer for!  hojop25 |
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01/07/2014 04:14:21 AM · #23465 |
Originally posted by Stagolee:
Young Josh has a lot to answer for! hojop25 |
LOL - Starting this thread was his last post - 2 years ago! |
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01/07/2014 08:30:04 AM · #23466 |
Originally posted by Art Roflmao:
Spork rhymes with Dork and All rhymes with Fall and that's what you just did. I win again. |
And Art rhymes with Fart
Spork wins |
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01/11/2014 03:14:33 AM · #23467 |
| nothing rhymes with Claudia |
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01/11/2014 11:40:31 AM · #23468 |
Originally posted by the99:
nothing rhymes with Claudia |
Unless I applaud ya.
But I can't because you lose and I win. :P |
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01/11/2014 04:20:40 PM · #23469 |
Applause, applause, applause. I found a place at DPChallenge where I can declare - I win!
Can I have a ribbon? |
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01/13/2014 10:53:08 AM · #23470 |
| Hi. Sorry for my absence. I've been thinking a lot about the next problem, and I finally cracked it last night during a fitful sleep. Given k >= 0, let P_k denote the family of all k-degenerate graphs, and for some graph G, let X_(P_k)(G) represent the minimum number of partitions of the vertices of V(G) necessary for each partition to induce a k-degenerate subgraph of G. A graph G is said to be l-critical with respect to X_(P_k) if X_(P_k)(G) = l but X_(P_k)(G - v) = l - 1 for every v in G. I intend to show that d(G) >= (k + 1)(l - 1). |
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01/13/2014 11:00:45 AM · #23471 |
Best of luck with your intentions.
In more important matters, Spork wins.
And builds a garden robot. |
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01/14/2014 03:11:42 PM · #23472 |
| I lost my fifteen minutes of fame and applause. bad luck ! |
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01/14/2014 04:04:59 PM · #23473 |
You've had almost an hour...
The stage and the victory belong to Spork.
Spork wins. |
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01/14/2014 04:50:16 PM · #23474 |
Originally posted by bvy:
Hi. Sorry for my absence. I've been thinking a lot about the next problem, and I finally cracked it last night during a fitful sleep. Given k >= 0, let P_k denote the family of all k-degenerate graphs, and for some graph G, let X_(P_k)(G) represent the minimum number of partitions of the vertices of V(G) necessary for each partition to induce a k-degenerate subgraph of G. A graph G is said to be l-critical with respect to X_(P_k) if X_(P_k)(G) = l but X_(P_k)(G - v) = l - 1 for every v in G. I intend to show that d(G) >= (k + 1)(l - 1). |
Wow, no one caught that. The last statement is unqualified. It should read:
I intend to show that if G is l-critical with respect to X_(P_k) then d(G) >= (k + 1)(l - 1).
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01/17/2014 01:11:19 AM · #23475 |
I come back to win?
Message edited by author 2014-01-17 01:11:38. |
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