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DPChallenge Forums >> General Discussion >> What is your DPC Quotient?
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Showing posts 26 - 50 of 53, (reverse)
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03/11/2005 07:50:20 AM · #26
Originally posted by lnede:

Here's one just for the fun of it. Multiply your average votes received by the number of challenges you have entered to get your "DPC Quotient". For instance, if you have entered 25 challenges and your average score is a 5.246 than your DPC Quotient is 131.15.


Just being pedantic, but isn't it a product, rather than a quotient?
03/11/2005 08:19:49 AM · #27
267.007
Is that good, bad or just numbers?
03/11/2005 08:47:46 AM · #28
Hows about, Average vote X no. of Fav photos / number of challenges entered. Its a bit fairer if you havent been here too long!

Mine is 18.39

03/11/2005 08:54:17 AM · #29
882.927
03/11/2005 09:07:49 AM · #30
1016.80 is this good?

-danny
03/11/2005 09:12:58 AM · #31
646.427

?? Still clueless about the meaning behind it!
03/11/2005 09:16:34 AM · #32
There is no good or bad in this formula. Because X,Y basis is depending on your average and # of challenges entered. Therefore someone could have entered 25 challenges and have 6.0 avg. votes received and have a lower number with this formula than a person that has entered 50 challenges and has a 4.0 avg. vote received.

User A has(6.0 x 25 = 150) and is equal to user B(3.0 x 50 = 150); Which is better? Neither, there are equal.

Message edited by author 2005-03-11 09:17:05.
03/11/2005 09:17:11 AM · #33
basically it adds all your scores together into one number. Doesn't show anything apart from your total rating really. If you can even call it that.
03/11/2005 09:20:22 AM · #34
128.305
03/11/2005 09:33:01 AM · #35
Originally posted by SDW65:

There is no good or bad in this formula. Because X,Y basis is depending on your average and # of challenges entered. Therefore someone could have entered 25 challenges and have 6.0 avg. votes received and have a lower number with this formula than a person that has entered 50 challenges and has a 4.0 avg. vote received.

User A has(6.0 x 25 = 150) and is equal to user B(3.0 x 50 = 150); Which is better? Neither, there are equal.


I would much prefer to be user A!!!

Have to agree with you Scott, the number this way is meaningless - why not just compare avg score to avg score???
03/11/2005 10:03:23 AM · #36
I think a better formula for calculating a rank or sort for users would be to compare (A)avg. votes cast and (B)avg. votes received compared to the scale avg. of 5.5

EXAMPLE:
Taken from my Profile
(A)avg. Vote Cast = 5.0955
(B)avg. Vote Received = 5.1435
(C)1-10 Scale Avg. = 5.5000
(X)Avg. Vote Sum
(Y)Your Score

Formula
(A + B)/2 = X
(X - C) = Y

(5.0955 + 5.1435)/2 = 5.1195
(5.1195 - 5.5000) = -0.4305

The goal is to get into the positive numbers. Low voting hurts just the same as low scoring.
Try this formula.
03/11/2005 10:15:31 AM · #37
Hmmm...that's interesting. Basically, if you avg 5.5 for giving and receiving you would be at 0. Better to give than receive? ;^)

(5.4154 + 5.3067)/2 = 5.3611
(5.3611 - 5.5000) = -0.1389
03/11/2005 10:28:33 AM · #38
Actually, where I was going with this and the reason I was calling it A "DPC Quotient" was a comparison between longevity on DPC and the ability to submit appealing pictures. It gives credit to those who have not only been members on DPC for a long time, but also those who have consistently submitted appealing pictures. For instance Someone like GeneralE has entered in almost every challenge since the site began gets credit for his loyalty to the site. Contrarily, Jibeguin has consistently submitted appealing pictures but has not submitted as many as GeneralE. Both recieve high scores in different ways for their dedication to DPC and what this website stands for in my opinion.
03/11/2005 11:35:55 AM · #39
This is all in good fun, fun to mess around with different descriptors as it were, but in good fun I have to say that SDW's number is fatally flawed: it would "encourage" artificial inflation of votes to get a "better" number.

If the "goal" of this "rating" is to measure dedication to DPC, as Inede has stated, then a better number might be one that factors challenges entered, average votes received, and number of comments made. Perhaps {(challenges entered) x average vote received) + (number of comments made + number of forum posts made) / 10}. Or something like that.

Challenges Entered: 20
Votes Cast: 5824
Avg Vote Cast: 4.9868
Votes Received: 5377
Avg Vote Received: 5.0136
# Comments:Made: 1149
# Helpful: 946
# Received: 345
Forum Posts: 1840

(20 x 5.0138) + (1149 + 1840) / 10 = 309.116 is my number.

Challenges Entered: 81
Votes Cast: 10695
Avg Vote Cast: 5.7143
Votes Received: 17248
Avg Vote Received: 5.7870
# Comments:Made: 404
# Helpful: 243
# Received: 2045
Forum Posts: 421
Profile Viewed: 44456 times

GriGri girl's number would be 129.3747

Challenges Entered: 255
Votes Cast: 21845
Avg Vote Cast: 6.2012
Votes Received: 51174
Avg Vote Received: 4.6328
# Comments:Made: 2854
# Helpful: 1361
# Received: 2801
Forum Posts: 11935
Profile Viewed: 15993 times

a whopping 2144.3387 for the general....

This number is heavily biased towards frequent commenters/posters. If you wanted the entries x quality part to have more weight, divide the sum of comments + forum posts by 10 and add that to the guotient of entries x average vote received.

Robt.
03/11/2005 11:43:09 AM · #40
Figured mine according to Robert. 106.2442

Not bad I think considering I have only been here 2 months.
03/11/2005 11:52:16 AM · #41
Originally posted by bear_music:

If you wanted the entries x quality part to have more weight, divide the sum of comments + forum posts by 10 and add that to the guotient of entries x average vote received.

Robt.


then divide by the square root of Pi and
multipy by the length of time in seconds, you can eat a doughnut, before licking your lips...
03/11/2005 11:57:47 AM · #42
Fun with numbers, Artan, fun with numbers....

Robt.
03/11/2005 11:59:25 AM · #43
Originally posted by bear_music:

Fun with numbers, Artan, fun with numbers....

Robt.


and food ..... Pi and Doughnuts
03/11/2005 12:07:14 PM · #44
There is always the very simple.

(Highest score, plus lowest score, plus the average score) x 10 to make it feel bigger.

This would demonstrate a measure of quality and consistency

making mine 157.895


Message edited by author 2005-03-11 12:11:44.
03/11/2005 12:10:35 PM · #45
Everytime I post in these forums my number goes up using Robert's way. so I am postin again.

Message edited by author 2005-03-11 14:24:19.
03/11/2005 02:09:48 PM · #46
10 entries: 55.758 <---Poser
03/11/2005 02:15:19 PM · #47
Originally posted by Artan:

There is always the very simple.

(Highest score, plus lowest score, plus the average score) x 10 to make it feel bigger.

This would demonstrate a measure of quality and consistency

making mine 157.895


I's like that one a LOT better if we could throw out my self-portrait score LOL. 146.95...

Actually, why include the lowest? Average plus best x 10.... Yeah, that works...

jejejeĆ¢„Ā¢

Robt.
03/11/2005 02:17:32 PM · #48
28 entires * avg 5.8797 = 164.63
I need to participate a lot more
03/11/2005 02:33:34 PM · #49
All this "New Math" ... it make my head spin:)

My number is 221.78.

I did not figure the comments or posts, I am a pretty heavy commenter, although sometimes my comments are simple "Nice shot".


03/11/2005 03:00:47 PM · #50
Ok - I put my foot firmly on the floor to make the spinning stop and came up with 149.9848.

Does that mean I'm still a rookie? or do I just suck at math? Where is the math guy when you need him?
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