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07/06/2003 08:04:00 PM · #1 |
I had a note from the administrators, saying if I resampled my print, I may be able to get 16x20 available. I thought that I could never get this, 'cause my prints were only so big to begin with. I submitted it full size. Is there some way to get the dpi needed for a larger size? I don't follow |
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07/06/2003 08:06:59 PM · #2 |
Read John's Tutorial on sizing for print.
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07/06/2003 08:22:42 PM · #3 |
| Yes! John's tutorial is excellent! However, as he states, you can only resample up to about twice it's original size. |
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07/06/2003 09:26:44 PM · #4 |
| thanks for that. Yeah, starting from 72 dpi I cant get it up to 150 dpi. They suggested resampling it to make a 16x20 available, but I guess I cannot |
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07/06/2003 09:30:38 PM · #5 |
| The dpi of the image "doesn't matter," what counts is the total number of pixels. For a 20" image you need a minimum of 3000 pixels in that dimension; 6000 would be optimum. |
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07/06/2003 10:01:05 PM · #6 |
| could someone clear this up for me? As I saw it, a higher dpi and enlarging the image are the opposite actions. If I am to get something 3000+ dots across, how can I enlarge to the dpi I need? |
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07/06/2003 10:13:14 PM · #7 |
Do read through John's tutorial. In a nutshell, your camera takes an image that is 2274x1704 (or thereabouts). You get the final print dimension by dividing the pixel count by the dpi. Or, you get the required number of pixels by multiplying the print dimension by the desired dpi.
So, when someone sez you should have 3000+ pixels across a 20 inch image, they are really saying you want at least 150dpi, which is very true. And 6000 px (300dpi) is better.
You can safely double your linear pixel count, so you will have 2*2274=4558 pixels on the longest side, yielding 228dpi. This should be adequate for a 16x20. |
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07/06/2003 10:20:32 PM · #8 |
Originally posted by hortopth:
could someone clear this up for me? As I saw it, a higher dpi and enlarging the image are the opposite actions. If I am to get something 3000+ dots across, how can I enlarge to the dpi I need? |
That is the essence of re-sampling: getting more inches at the same DPI. The software basically spreads your pixels apart, analyzes the color of the surrounding pixels, and creates a new pixel to fill the space created. That's why there's a risk of losing detail, and why some images will enlarge easier than others.
For the print image, I took my photo Blaze of Glory and just enlarged it to 200% with IrfanView, because with all the smooth gradients and lack of detail the software handled it pretty efficiently.
Message edited by author 2003-07-06 22:24:58. |
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07/06/2003 10:56:22 PM · #9 |
Originally posted by kirbic:
Do read through John's tutorial. In a nutshell, your camera takes an image that is 2274x1704 (or thereabouts). You get the final print dimension by dividing the pixel count by the dpi. Or, you get the required number of pixels by multiplying the print dimension by the desired dpi.
So, when someone sez you should have 3000+ pixels across a 20 inch image, they are really saying you want at least 150dpi, which is very true. And 6000 px (300dpi) is better.
You can safely double your linear pixel count, so you will have 2*2274=4558 pixels on the longest side, yielding 228dpi. This should be adequate for a 16x20. |
Thanks, Fritz, for that clarification. When I use photoshop, I use the crop tool and set it to 10 in x 8 in (or whatever my dimensions are). After it's cropped, the image will be 10 x 8 with a dpi of, usually, between 200 and 230 dpi. Then I resample until it is at least 300 dpi. So if I start at 210 dpi, I can resample to 420 dpi, though I usually try to stay about 3/4 back, so around 360 or so.
I have resampled some of my images too high, even though they were not even doubled. Luckily, Drew or Langdon or someone in DPCPrints checked it and sent me a kind not saying it was rejected for over-resampling--far better than selling someone a lousy print! |
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